CHEM 1405: Akeia Scott Transformations. Worked Solutions. 100% | Documents and Forms | Research Papers

CHEM 1405: Akeia Scott Transformations. Worked Solutions. 100%

CHEM 1405: Akeia Scott Transformations. Worked Solutions. 100% PLDZ-10
In Stock
$ 9.00 USD
Buy and Download   > Description

Akeia Scott 9/18/18 Transformations Explain how the graph of the given function is a transformation of the graph of y=x^2. 1. y=x^2+7 up 7 units 2. y=x^2-11 down 11 units 3. y =(x-1)^2 right 1 unit 4. y=(x+5) left 5 units 5. y=4x^2 Stretched by a factor of 4 6. y=1/2x^2 compressed by a factor of 2 7. y=(1/2x)^2 8. y=-(x-1)^2 flipped over the x-axis and shifted right 1 unit. 9. y=(-x-3)^2 shift left 3 units 10. y=(2x-6)^2+5 shift right 3 units, vertical stretch by a factor of 2, then a vertical shift up 5 units. 11. y=2(1/2(x+2))^2-7 vertical shift down 7 units. Write a function for the graph described as a transformation of y=x^2. 12. y=x^2 experiences a vertical stretch of factor 2 and then a shift right of 3 units. y=2(x−3)^2 13. y=x^2 experiences a shift left by 2 units, then a horizontal shrink factor of 1/2, then a shift down of 5 units. y=1/2(x+2)^2−5 14. y=x^2 experiences a shift to the right 1 unit, is stretched vertically by a factor of 1/2, then is shifted down 4 units. y=1/2(x−1)^2−4 15. y=x^2is reflected across the x-axis, stretched vertically by a factor of 3, and shifted left 7 units. y=−3(x+7)^2 The graph is that of a function that results from transforming y=x^2. Write an explicit function for y=f: 16. y=−(x+5)^2−3 17. y=x^2−4 18. y=−1/2(x−2)^2+6 19. y=(x−1)^2+1 Match the function to its graph. Show Less

 

Akeia Scott 9/18/18 Transformations Explain how the graph of the given function is a transformation of the graph of y=x^2. 1. y=x^2+7 up 7 units 2. y=x^2-11 down 11 units 3. y =(x-1)^2 right 1 unit 4. y=(x+5) left 5 units 5. y=4x^2 Stretched by a fac
Recent Reviews Write a Review
0 0 0 0 reviews