MA240Week 10 ChiTest and the FDistribution
MA240Week 10 ChiTest and the FDistribution
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 What conditions are necessary to use the chisquare goodnessoffit test?
 Find the expected frequency, Ei, for the given values of n and pi.
n = 140, pi = 0.6
 A survey was conducted two years ago asking college students their top motivations for using a credit card. To determine whether this distribution has changed, you randomly select 425 college students and ask each one what the top motivation is for using a credit card. Can you conclude that there has been a change in the claimed or expected distribution? Use α = 0.10. Complete parts (s) through (d).
 State H0 and Ha and identify the claim.
 Determine the critical value, χ20, and the rejection region.
 Calculate the test statistic.
 Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim.
 The national distribution of fatal work injuries in a country is shown in the table to the right under National %. You believe that the distribution of fatal work injuries is different in the western part of the country and randomly select 6231 fatal work injuries occurring in that region. At α = 0.10 can you conclude that the distribution of fatal work injuries in the west is different from the national distribution? Complete parts a through d below.
 State H0 and Ha and identify the claim.
 Determine the critical value, χ20, and the rejection region.
 Calculate the test statistic.
 Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim.
 The frequency distribution shows the results of 200 test scores. Are the test scores normally distributed? Use α = 0.05. Complete parts (a) through (d).
Class boundaries






Frequency, f

19

60

84

33

4

Using a chisquare goodnessoffit test, you can decide with some degree of certainty, whether a variable is normally distributed. In all chisquare test for normally, the null and alternative hypotheses are as follows.
H0: The test scores have a normal distribution.
Ha: The test scores do not have a normal distribution.
 Find the expected frequencies.
 Determine the critical value, χ20, and the rejection region.
 Calculate the test statistic.
 Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim.
 Determine whether the statement is true or false. If it is false, rewrite it as a true statement.
If the test statistic for the chisquare independence test is large, you will, in most cases, reject the null hypothesis.
 Use the contingency table to the right to calculate the marginal frequencies and find the expected frequency for each cell in the contingency table. Assume that the variables are independent.

Athlete has

Result

Stretched

Not stretched

Injury

17

20

No injury

203

183

 You want to determine whether the reason given by workers for continuing their education is related to job type. In the study, you randomly collect the data shown in the contingency table. At α = 0.01, can you conclude that the reason and type of worker are dependent? Complete parts (a) through (d).

Reason

Type of worker

Professional

personal

Both

Technical

38

36

35

Other

46

26

34

 Identify the claim and state the null and alternative hypotheses.
 Determine the degree of freedom, find the critical value, and identify the rejection region.
 Calculate the test statistic. If convenient, use the technology.
 Decide to reject or fail to reject the null hypothesis. Can you conclude that the reason and type of worker are dependent?
 The contingency table below shows the results of a sample of motor vehicle crash deaths by age and gender. At α = 0.025, perform a homogeneity of proportions test on the claim that the proportions of motor vehicle crash death involving males or females are the same for each group.
What conditions are necessary to use the chisquare goodnessoffit test?
Find the expected frequency, Ei, for the given values of n and pi.
n = 140, pi = 0.6
A survey was conducted two years ago asking college students their top motivations